## Intermediate Algebra: Connecting Concepts through Application

part a: $(0,7)$ part b: $(12,0)$ part c: -$14$ part d: $15$ part e: $13$
part a: By looking at the graph, the vertical intercept is where the line intersects the y-axis. That would be about 7. Written in proper form as an (x,y) coordinate, the answer would be $(0,7)$. part b: By looking at the graph, the horizontal intercept is where the line intersects the x-axis. That would be about 12. Written in proper form as an (x,y) coordinate, the answer would be $(12,0)$. part c: We know that we are looking for the input or x value that makes the output=15 or y=15 true. (x,15) is a better way to visualize this. At y=15 on the graph, the line reaches about -$14$ on the x-axis. part d: We know that we are looking for the input or x value that makes the output=-2 or y=-2 true. (x,-2) is a better way to visualize this. At y=-2 on the graph, the line reaches $15$ on the x-axis. part e: We know that we are looking for the output or y value that makes the input=-10 or x=-10 true. (-10,y) is a better way to visualize this. At x=-10 on the graph, the line reaches about $13$ on the y-axis.