Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1 - Linear Functions - 1.1 Solving Linear Equations - 1.1 Exercises - Page 13: 38


Rosemary had the correct equation because she took the 75+0.55b part of the equation out of the parentheses by using the "-" sign before it making 75 a negative and 0.55b a negative.

Work Step by Step

Rosemary did the problem correctly in using the original cost equation $C=75+0.55b$ and incorporating it with the revenue equation $R=0.95b$. So, profit is P=R-C or $P=0.95b-(75+0.55b)$, which then ends up being $P=0.95b-75-0.55b$, then $P=-75+0.40b$.
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