## Intermediate Algebra: Connecting Concepts through Application

Rosemary did the problem correctly in using the original cost equation $C=75+0.55b$ and incorporating it with the revenue equation $R=0.95b$. So, profit is P=R-C or $P=0.95b-(75+0.55b)$, which then ends up being $P=0.95b-75-0.55b$, then $P=-75+0.40b$.