## Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole

# Chapter 1-2 - Cumulative Review - Page 219: 49

#### Answer

$x\le-10 \text{ OR } x\ge2$

#### Work Step by Step

$\bf{\text{Solution Outline:}}$ To solve the given inequality, $|x+4|\ge6 ,$ use the definition of absolute value inequality. Use the properties of inequality to isolate the variable. Finally, graph the solution set. In the graph, a hollowed dot is used for $\lt$ or $\gt.$ A solid dot is used for $\le$ or $\ge.$ $\bf{\text{Solution Details:}}$ Since for any $c\gt0$, $|x|\gt c$ implies $x\gt c \text{ or } x\lt-c$ (which is equivalent to $|x|\ge c$ implies $x\ge c \text{ or } x\le-c$), the inequality above is equivalent to \begin{array}{l}\require{cancel} x+4\ge6 \\\\\text{OR}\\\\ x+4\le-6 .\end{array} Solving each inequality results to \begin{array}{l}\require{cancel} x+4\ge6 \\\\ x\ge6-4 \\\\ x\ge2 \\\\\text{OR}\\\\ x+4\le-6 \\\\ x\le-6-4 \\\\ x\le-10 .\end{array} Hence, the solution set is $x\le-10 \text{ OR } x\ge2 .$

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