Intermediate Algebra: Connecting Concepts through Application

a) $m = \frac{15}{4}$ b) $y = -5$ c) $x \approx 1.33...$ d) $y = \frac{15}{4}x - 5$
a) Slope of the line: Take two clear points on the line and find the slope. Points $(0, -5)$ and $(4,10)$. $m = \frac{10-(-5)}{4-0}$ $m = \frac{10+5}{4}$ $m = \frac{15}{4}$ b) Vertical intercept / $y$ intercept $y = -5$ at point $(0, -5)$, refer to the graph c) Horizontal intercept / $x$ intercept $x = 1.3$ at point $(\approx1.3,0)$, simply estimate the intersection. Since the $x$ intercept is not clear, you could double check using the equation in step d): $0 = \frac{15}{4}x - 5$ $5 = \frac{15x}{4}$ $20 = 15x$ $x = \frac{20}{15}$ $x = \frac{4}{3}$ $x \approx 1.33...$ d) Equation $y = mx + b$ $y = \frac{15}{4}x - 5$