## Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole

# Appendix A - Basic Algebra Review - A Exercises - Page A-14: 2

#### Answer

$\sqrt9$, which is equal to 3, is a natural number, a whole number, an integer, a rational number, and a real number.

#### Work Step by Step

RECALL: (i) Natural (or Counting) Numbers are $1, 2, 3, ...$ (ii) Whole Numbers are $0, 1, 2, 3, ...$ (ii) Integers are $..., -3, -2, -1, 0, 1, 2, 3, ...$ (iv) Rational Numbers are numbers that can be expressed as a quotient of two integers. (v) Irrational Numbers are numbers that cannot be expressed as a quotient of two integers. (vi) Real Numbers are the set of all rational and irrational numbers. $\sqrt9=\sqrt{3^2} = 3$. Thus, the number $\sqrt{9}$, which is equal to 3, is a natural number, a whole number, an integer, a rational number, and a real number.

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