Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Sections 9.1-9.6 - Integrated Review - Functions and Properties of Logarithms: 14


$ f^{-1}(x)=\frac{x+1}{5}$

Work Step by Step

We are given the function, $f(x)=5x-1$. First, we must replace $f(x)$ with y. $y=5x-1$ Next, interchange x and y. $x=5y-1$ Next, solve for y by adding 1 to both sides. $5y=x+1$ Divide both sides by 5. $y=\frac{x+1}{5}$ Finally, replace y with $f^{-1}(x)$. $ f^{-1}(x)=\frac{x+1}{5}$
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