Answer
$k=.0827$
Work Step by Step
$log_{10} (1-k) = -.3/H$
$H$ is half life
$H=8$
$log_{10} (1-k) = -.3/H$
$log_{10} (1-k) = -.3/8$
$log_{10} (1-k) = -.0375$
$10^{-.0375} =1-k$
$.91727=1-k$
$.91727+k-.91727=1-k+k-.91727$
$k=.08273$
$k=.0827$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 9 - Section 9.5 - Logarithmic Functions - Exercise Set - Page 573: 107
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