Answer
$x=-\frac{1}{7},-1$
Work Step by Step
$7x^{2}+8x+1=0$
$7x^{2}+1x+7x+1=0$
$x(7x+1)+1(7x+1)=0$
$(7x+1)(x+1)=0$
$(7x+1)=0$ and $(x+1)=0$
$x=-\frac{1}{7}$ and $x=-1$
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