Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Test - Page 532: 1

Answer

$x=\frac{7}{5},-1$

Work Step by Step

$5x^{2}-2x=7$ $5x^{2}-2x-7=0$ $5x^{2}+5x-7x-7=0$ $5x(x+1)-7(x+1)=0$ $(x+1)(5x-7)=0$ $(x+1)=0$ and $(5x-7)=0$ $x=-1$ and $x=\frac{7}{5}$
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