Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Sections 8.1-8.3 - Integrated Review - Summary on Solving Quadratic Equations - Page 505: 29

Answer

$x=\left\{ -\dfrac{1}{2},\dfrac{1}{3} \right\}$

Work Step by Step

Multiplying both sides by the $LCD= x(x-2) ,$ the solution to the given equation, $ \dfrac{5x}{x-2}-\dfrac{x+1}{x}=\dfrac{3}{x(x-2)} ,$ is \begin{array}{l}\require{cancel} x(5x)-(x-2)(x+1)=1(3) \\\\ 5x^2-(x^2+x-2x-2)=3 \\\\ 5x^2-(x^2-x-2)=3 \\\\ 5x^2+x^2+x+2-3=0 \\\\ 6x^2+x-1=0 \\\\ (2x+1)(3x-1)=0 \\\\ x=\left\{ -\dfrac{1}{2},\dfrac{1}{3} \right\} .\end{array}
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