Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Section 8.5 - Quadratic Functions and Their Graphs - Exercise Set: 69



Work Step by Step

The vertex-form of a quadratic equation is $y=a(x-h)^{2}+k$, with a vertex at the opposite of $h$ and $k$, or $(h, k)$. The original equation in this problem is $f(x)=5x^{2}$; written in vertex-form it is $f(x)=5(x-0)^{2}+0$ and has a vertex of $(0, 0)$. To translate this parabola so that the vertex is at $(2, 3)$ we need to rewrite the equation as $f(x)=5(x-2)^{2}+3$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.