Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Test - Page 470: 5

Answer

$\dfrac{4x^2}{9}$

Work Step by Step

Using $a^{m/n}=\sqrt[n]{a^m}$, the expression $ \left( \dfrac{8x^3}{27} \right)^{2/3} $ simplifies to \begin{array}{l} \left( \sqrt[3]{\dfrac{8x^3}{27}} \right)^2 \\\\= \left( \dfrac{2x}{3} \right)^2 \\\\= \dfrac{4x^2}{9} .\end{array}
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