Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.7 - Complex Numbers - Vocabulary, Readiness & Video Check - Page 462: 10

Answer

$\sqrt -32$ = 4i$\sqrt 2$

Work Step by Step

$\sqrt -32$= i$\sqrt 32$= Rewrite in terms of i. (i=$\sqrt -1$) i$\sqrt 16$$\sqrt 2$= Simplify $\sqrt 32$ 4i$\sqrt 2$ Simplify $\sqrt 16$ to get final answer
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.