Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.6 - Radical Equations and Problem Solving - Exercise Set - Page 454: 62

Answer

$\text{ approximately } 24 \text{ } ft$

Work Step by Step

Let $x$ be the height from the ground where the wire will be attached. Using $a^2+b^2=c^2$ or the Pythagorean Theorem, the conditions of the problem translate to \begin{array}{l}\require{cancel} 15^2+x^2=(30-2)^2 .\end{array} Using the properties of equality, the equation above is equivalent to \begin{array}{l}\require{cancel} x^2=(30-2)^2-15^2 \\ x^2=28^2-15^2 \\ x^2=784-225 \\ x^2=559 .\end{array} Taking the square root of both sides, the equation above is equivalent to \begin{array}{l}\require{cancel} x=\sqrt{559} \\ x\approx24 .\end{array} Hence, the height from the ground where the wire will be attached, $x,$ is $ \text{ approximately } 24 \text{ } ft .$
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