#### Answer

$\frac{\sqrt[3] 4}{3}$

#### Work Step by Step

The quotient rule holds that $\sqrt[n] (\frac{a}{b})=\frac{\sqrt[n] a}{\sqrt[n] b}$ (where $\sqrt[n] a$ and $\sqrt[n] b$ are real numbers and $\sqrt[n] b$ is nonzero).
Therefore, $\sqrt[3] (\frac{4}{27})=\frac{\sqrt[3] 4}{\sqrt[3] 27}=\frac{\sqrt[3] 4}{3}$
We know that $\sqrt[3] 27=3$, because $3^{3}=27$.