Answer
False
Work Step by Step
$9^{-\frac{1}{2}}=\frac{1}{(9)^{\frac{1}{2}}}=\frac{1}{\sqrt 9}=\frac{1}{3}$
$\frac{1}{3}$ is a fraction, so it is not a whole number We know that $\sqrt 9=3$, because $3^{2}=9$
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