## Intermediate Algebra (6th Edition)

$y^{\frac{1}{4}}$
Let the missing term be $x$ The given expression becomes, $\frac{x}{y^{\frac{-3}{4}}}= y^{\frac{4}{4}}$ $x=y^{\frac{-3}{4}} \times y^{\frac{4}{4}}$ Using product rule for exponents, $a^{m} \times a^{n} = a^{m+n}$ $x=y^{\frac{-3}{4} + \frac{4}{4} }$ $x=y^{\frac{-3+4}{4} }$ $x=y^{\frac{1}{4} }$