Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Vocabulary, Readiness & Video Check - Page 416: 14



Work Step by Step

$\sqrt 9\lt\sqrt 11\lt\sqrt 16$ $3\lt\sqrt 7\lt4$ The approximation is reasonable because $\sqrt 11$ (3.316), is greater than $\sqrt 9$ (3) but less than $\sqrt16$ (4).
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