Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.5 - Solving Equations Containing Rational Expressions - Exercise Set - Page 378: 47

Answer

$x=-\dfrac{7}{5}$

Work Step by Step

The factored form of the given equation, $ \dfrac{x+2}{x^2+7x+10}=\dfrac{1}{3x+6}-\dfrac{1}{x+5} ,$ is \begin{array}{l}\require{cancel} \dfrac{x+2}{(x+5)(x+2)}=\dfrac{1}{3(x+2)}-\dfrac{1}{x+5} .\end{array} Multiplying both sides by the $LCD= 3(x+5)(x+2) ,$ then the solution to the given equation is \begin{array}{l}\require{cancel} 3(x+2)=(x+5)(1)-3(x+2)(1) \\\\ 3x+6=x+5-3x-6 \\\\ 3x-x+3x=5-6-6 \\\\ 5x=-7 \\\\ x=-\dfrac{7}{5} .\end{array}
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