Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.5 - Solving Equations Containing Rational Expressions - Exercise Set - Page 377: 14

Answer

x = 15

Work Step by Step

Original Equation $\frac{6}{x+3}$ = $\frac{4}{x-3}$ Multiply equation by the LCD, (x+3)(x-3) to get rid of denominators 6(x-3) = 4(x+3) Distribute 6x-18 = 4x+12 Simplify 2x = 30 Divide by 2 to find x x = 15
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