Answer
$$ \frac{2y+x}{y-2x}$$
Work Step by Step
First, we create a common denominator:
$$ \frac{ \frac{2y^2-xy-x^2}{x^2y^2}}{\frac{y^2-3xy+2x^2}{x^2y^2}}$$
We cancel the common terms to find:
$$ \frac{2y^2-xy-x^2}{y^2-3xy+2x^2}$$
We factor to find:
$$ \frac{(2y+x)(y-x)}{(y-2x)(y-x)}$$
This gives the answer:
$$ \frac{2y+x}{y-2x}$$
