#### Answer

$(x-1)(x^2+x+1)(x+1)(x^2-x+1)$

#### Work Step by Step

Using $a^2-b^2=(a+b)(a-b)$ and $a^3-b^3=(a-b)(a^2+ab+b^2)$, then the given expression, $
x^6-1
$, is equivalent to
\begin{array}{l}
(x^3-1)(x^3+1)
\\\\
(x-1)(x^2+x+1)(x^3+1)
\\\\
(x-1)(x^2+x+1)(x+1)(x^2-x+1)
.\end{array}