Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.5 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 296: 84

Answer

$4\pi r^{2}(1+\frac{1}{3}r)$

Work Step by Step

In order to factor out $4\pi r^{2}$ from $4\pi r^{2}+\frac{4}{3}\pi r^{2}$, use the distributive property. $4\pi r^{2}(1)+4\pi r^{2}(\frac{1}{3}r)$ This takes $4\pi r^{2}$ out of the parenthesis. After simplifying, you are left with: $4\pi r^{2}(1+\frac{1}{3}r)$.
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