Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.5 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 295: 16

Answer

$6ab(2a^2-1+3b-3a)$

Work Step by Step

Factoring the $GCF= 6ab $, then, \begin{align*} 12a^3b-6ab+18ab^2-18a^2b \Rightarrow 6ab(2a^2-1+3b-3a) .\end{align*}
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