Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.3 - Polynomials and Polynomial Functions - Exercise Set - Page 279: 20

Answer

79

Work Step by Step

We can find the value of $Q(4)$ by plugging 4 into the formula for $Q(x)$. $Q(x)=5x^{2}-1$ $Q(4)=5(4^{2})-1=5\times(4\times4)-1=5\times16-1=80-1=79$
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