Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.2 - More Work with Exponents and Scientific Notation - Vocabulary, Readiness & Video Check - Page 267: 4

Answer

$x^{15}$

Work Step by Step

We are given the expression $x^{7}\times x^{8}$. We can use the product rule to simplify, which holds that $a^{m}\times a^{n}=a^{m+n}$ (where a is a real number, and m and n are positive integers). $x^{7}\times x^{8}=x^{7+8}=x^{15}$
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