Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Sections 4.1-4.3 - Integrated Review - Systems of Linear Equations - Page 235: 22

Answer

Angles are $70°, 70°,100°,120°$.

Work Step by Step

Let four angels of the quadrilateral be $x°, y°, z°$ and $w°$. Two smallest angles be $x°$ and $y°$. They have same measure. So, $x° = y°$ Equation $(1)$. Third angle $(z°)$ measures $30°$ more than the measure of one of the smallest angle. $z°= x° + 30°$ Equation $(2)$ Fourth angle $(w°)$ measures $50$ more than the one of the smallest angle then $w° = x° + 50°$ Equation $(3)$ Sum of the measures of the quadrilateral is $360°$ $x°+y°+z°+w° = 360°$ Equation $(4)$ Substituting the values from Equations $(1)$, $(2)$, $(3)$ in Equation $(4)$, we get $x°+y°+z°+w° = 360°$ $x°+x°+x°+30°+x°+50° = 360°$ $4x° +80° = 360°$ $4x° = 360° - 80°$ $4x° = 280°$ $x° = 70°$ $ y° = x° = 70° $ $z°= x° + 30° = 70° + 30° = 100°$ $w° = x° + 50° = 70° + 50° = 120°$ Angles are $70°, 70°,100°,120°$.
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