Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Section 4.3 - Systems of Linear Equations and Problem Solving - Exercise Set - Page 231: 11

Answer

There are $9$ large frames and $13$ small frames.

Work Step by Step

Let $x$ represent the number of large frames and let $y$ be the number of small frames. $15x + 8y = 239$ Equation $(1)$ $x + y = 22$ $y = 22 - x$ Equation $(2)$ Substitute $y$ into Equation $(1)$. $15x + 8(22 - x) = 239$ $15x + 176 - 8x = 239$ $7x = 63$ $x = 9$ Substitute $x$ into Equation $(2)$. $y = 22-9$ $y = 13$ There are $9$ large frames and $13$ small frames.
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