Answer
The equations $ a,b$ and $d $ has $(-1,3,1)$ as a solution.
Work Step by Step
Substituting $x=-1$, $y=3$, $z= 1$ in
a. $x+y+z = 3$
$-1+3+1=3$
$3 = 3$
b. $-x+y+z = 5$
$-(-1)+3+1= 5$
$1+3+1= 5$
$5=5$
c. $-x+y+2z=0$
$-(-1)+3+2(1)=0$
$1+3+2 =0$
$6 \ne 0$
d. $x+2y-3z =2$
$-1+2(3)-3(1)= 2$
$-1+6-3 = 2$
$2 = 2 $
Ordered triple $(-1,3,1)$ makes the equations $ a,b$ and $d $ a true statement. So, the equations $ a,b$ and $d $ has $(-1,3,1)$ as a solution.
