Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Review - Page 250: 24

Answer

The numbers are $120,115,60$

Work Step by Step

Let the numbers be $x,y,z$ Sum of three numbers is $295$ $x+y+z=295$ Equation $(1)$ One number is 5 more than the second and twice the third. $x=5+y$ $y= x- 5$ Equation $(2)$ $x= 2z$ $z=\frac{x}{2}$ Equation $(3)$ Substituting $y$ and $z$ in Equation $(1)$ $x+y+z=295$ $x+x-5+\frac{x}{2}=295$ $2x+\frac{x}{2}=295+5$ $2x+\frac{x}{2}=300$ $\frac{4x+x}{2}=300$ $5x=600$ $x= 120$ From Equation $(2)$ and Equation $(3)$ $y= x- 5$ $y= 120- 5$ $y= 115$ $z=\frac{x}{2}$ $z=\frac{120}{2}$ $z=60$ The numbers are $120,115,60$
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