Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Cumulative Review - Page 252: 29b

Answer

$g(1)=1$

Work Step by Step

To find the value of $g(1)$, substitute 1 to $x$ in the function $g(x)$ to have: $\\\\g(x) = 3x-2 \\\\g(1) = 3(1)-2 \\\\g(1)=3-2 \\\\g(1)=1$
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