Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Sections 3.1-3.5 - Integrated Review - Linear Equations in Two Variables - Page 176: 20

Answer

$4x-5y=10$ $5y=4x-10$ $y=\frac{4}{5}x-2$ The new slope is the negative reciprocal of $\frac{4}{5}$. The new slope is $-\frac{5}{4}$. Use point-slope form: $y-4=-\frac{5}{4}x$ $f(x)=-\frac{5}{4}x+4$

Work Step by Step

$4x-5y=10$ $5y=4x-10$ $y=\frac{4}{5}x-2$ The new slope is the negative reciprocal of $\frac{4}{5}$. The new slope is $-\frac{5}{4}$. Use point-slope form: $y-4=-\frac{5}{4}x$ $f(x)=-\frac{5}{4}x+4$
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