## Intermediate Algebra (6th Edition)

$4x-5y=10$ $5y=4x-10$ $y=\frac{4}{5}x-2$ The new slope is the negative reciprocal of $\frac{4}{5}$. The new slope is $-\frac{5}{4}$. Use point-slope form: $y-4=-\frac{5}{4}x$ $f(x)=-\frac{5}{4}x+4$
$4x-5y=10$ $5y=4x-10$ $y=\frac{4}{5}x-2$ The new slope is the negative reciprocal of $\frac{4}{5}$. The new slope is $-\frac{5}{4}$. Use point-slope form: $y-4=-\frac{5}{4}x$ $f(x)=-\frac{5}{4}x+4$