Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Section 3.7 - Graphing Linear Inequalities - Exercise Set - Page 188: 63

Answer

$\dfrac{27}{125}$

Work Step by Step

Using the concepts of exponents, the given expression, $ \left( \dfrac{3}{5} \right)^3 ,$ is equivalent to \begin{array}{l}\require{cancel} \left( \dfrac{3}{5} \right)\left( \dfrac{3}{5} \right)\left( \dfrac{3}{5} \right) \\\\= \dfrac{27}{125} .\end{array}
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