Answer
Please see the graph.
Work Step by Step
Green line: $x-y>2$
$x-y>2$
$x-y+y-2>2+y-2$
$x-2>y$
Let's use $(0,0)$ to see if this point is a solution of the graph.
$x-2>y$
$0-2>0$
$-2>0$ (false)
$(0,0)$ is not a solution of the graph, so we'll shade the other side of the line.
Red line: $y<5$
Let's use $(0,0)$ to see if this point is a solution of the graph.
$y<5$
$0<5$ (true)
$(0,0)$ is a solution of the graph, so we shade that side of the line.
The union of the two lines is where the graph is shaded either red or green.
