Answer
$\left(-\infty, \dfrac{1}{3} \right)$
Work Step by Step
Using the properties of inequality, the solution to the given expression, $
-3x+1\gt0
,$ is
\begin{array}{l}\require{cancel}
-3x\gt-1
\\\\
x\lt\dfrac{-1}{-3}
\\\\
x\lt\dfrac{1}{3}
.\end{array}
Hence, the solution is $
\left(-\infty, \dfrac{1}{3} \right)
.$
