## Intermediate Algebra (6th Edition)

$y=-\frac{3}{2}x+2$
$3y=2x-1$ $y=\frac{2}{3}x-\frac{1}{3}$ The slope of the new line is the negative reciprocal of $\frac{2}{3}$: $-\frac{3}{2}$. Use point slope form: $y-8=-\frac{3}{2}(x+4)$ $y=-\frac{3}{2}x-6+8$ $y=-\frac{3}{2}x+2$