## Intermediate Algebra (6th Edition)

$7x+4y=8$
Substituting $x=0$ in the given equation, $7x+4y=8 ,$ results to \begin{array}{l}\require{cancel} 7x+4y=8 \\ 7(0)+4y=8 \\ 4y=8 \\ y=\dfrac{8}{4} \\ y=2 .\end{array} Substituting $y=0$ in the given equation, $7x+4y=8 ,$ results to \begin{array}{l}\require{cancel} 7x+4y=8 \\ 7x+4(0)=8 \\ 7x=8 \\ x=\dfrac{8}{7} .\end{array} Substituting $y=-1$ in the given equation, $7x+4y=8 ,$ results to \begin{array}{l}\require{cancel} 7x+4y=8 \\ 7x+4(-1)=8 \\ 7x-4=8 \\ 7x=8+4 \\ 7x=12 \\ x=\dfrac{12}{7} .\end{array} The table below summarizes the results above. It is also used to graph the given equation.