Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Review - Page 194: 7

Answer

a. 9 b. $\frac{1}{16}$ c. -25 d. 25 e. -125 f. -125

Work Step by Step

7a $3^2$ $3\times3$ $9$ 7b $(\frac{1}{2})^4$ $\frac{1*1*1*1}{2*2*2*2}$ $\frac{1}{16}$ 7c $-5^2$ $-25$ 7d $(-5)^2$ $(-5)\times(-5)$ $25$ 7e $-5^3$ $-(5\times5\times5)$ $-125$ 7f $(-5)^3$ $(-5)\times(-5)\times(-5)$ $-125$
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