Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Review - Page 194: 4

Answer

4a. 7 4b. 0 4c. $-\frac{1}{4}$

Work Step by Step

4a. $-7(-1)=7$ 4b. $0(-1)=0$ 4c. $\frac{1}{4}(-1)=-\frac{1}{4}$
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