Answer
$6,720,000 \text{ cars}$
Work Step by Step
Let $x$ be the number of new vehicles sold in $2003.$
The conditions of the problem translate to the equation
\begin{array}{l}\require{cancel}
x-0.2832x=4817000
.\end{array}
Using the properties of equality, the equation above is equivalent to
\begin{array}{l}\require{cancel}
x-0.2832x=4817000
\\
0.7168x=4817000
\\
x=\dfrac{4817000}{0.7168}
\\
x=6720145.0892857142857142857142857
.\end{array}
Hence, to the nearest thousand, the number of vehicles sold in $2003$ is $
6,720,000 \text{ cars}
.$
