Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.6 - Absolute Value Equations - Exercise Set - Page 101: 73

Answer

There are a number of possible 5-integer solutions. One of them is: $-3, -2, -1, 0, 1$

Work Step by Step

RECALL: $|x| \le a \longrightarrow -a \le x \le a$ Thus, $|x| \le 3 \longrightarrow -3 \le x \le 3$ Therefore the following integers are solutions of the given inequality: $-3, -2, -1, 0, 1$
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