Answer
$\left(-\dfrac{101}{5}\right)^oF \text{ to }95^oF$
Work Step by Step
Using $C=\dfrac{5}{9}(F-32),$ then the equivalent range of Fahrenheit values for $-29^oC$ to $35^oC$ is
\begin{array}{l}\require{cancel}
-29\le\dfrac{5}{9}(F-32)\le35
.\end{array}
Using the properties of inequality, then
\begin{array}{l}\require{cancel}
\dfrac{9}{5}\left( -29 \right) \le\dfrac{9}{5}\cdot\dfrac{5}{9}(F-32)\le\dfrac{9}{5}\cdot35
\\\\
-\dfrac{261}{5} \le F-32\le63
\\\\
-\dfrac{261}{5}+32 \le F-32+32\le63+32
\\\\
-\dfrac{261}{5}+\dfrac{160}{5} \le F\le95
\\\\
-\dfrac{101}{5}\le F\le95
.\end{array}
Hence the equivalent range of temperature in Fahrenheit is $
\left(-\dfrac{101}{5}\right)^oF \text{ to }95^oF
.$
