## Intermediate Algebra (6th Edition)

$x\lt4$ or $(-\infty,4)$
Solve: $2x-3\lt5$ Take $3$ to the right side: $2x\lt5+3$ $2x\lt8$ Take $2$ to divide the right side: $x\lt\dfrac{8}{2}$ $x\lt4$ Expressing the solution in interval notation: $(-\infty,4)$