Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.3 - Formulas and Problem Solving - Exercise Set - Page 75: 51

Answer

$1,831.96

Work Step by Step

To solve this problem use the compound interest formula. $A=P(1+\frac{r}{n})^{nt}$ 10,000 is the principal amount, so $ P=10,000$. 8.5 percent is the interest rate, so $r=0.085$. The interest is compounded quarterly, so $n=4$. Because we are finding the amount of interest earned over 2 years, $t=2$. Plug the values into the original formula: $A=10,000(1+\frac{0.085}{4})^{4\times2}$ Multiply the exponents: $A=10,000(1+\frac{0.085}{4})^{8}$ Evaluate: $A=10,000(1+\frac{0.085}{4})^{4\times2}=11,831.96$ The question asks to find the amount of interest earned, so subtract the principal amount from your answer. $11,831.96-10,000= 1,831.96$ $1,831.96 is your answer.
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