Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.3 - Formulas and Problem Solving - Exercise Set - Page 74: 31

Answer

$C=40$ degrees

Work Step by Step

We are given that $F=104$ degrees. We can plug in this value into the given equation to solve for C. $C=\frac{5}{9}(F-32)=\frac{5}{9}(104-32)=\frac{5}{9}(72)=40$ degrees
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