Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.3 - Formulas and Problem Solving - Exercise Set: 23



Work Step by Step

We are given that $S=2LW+2LH+2WH$. We can solve for H by first subtracting 2LW from both sides. $S-2LW=2LH+2WH$ We can use the distributive property to factor out H from both terms on the right side. $S-2LW=H(2L+2W)$ Divide both sides by 2L+2W. $H=\frac{S-2LW}{2L+2W}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.