Answer
$F=\frac{9C+160}{5}$
Work Step by Step
We are given that $C=\frac{5}{9}(F-32)$. We can use the distributive property to multiply out the terms on the right side.
$C=\frac{5}{9}\times(F-32)=\frac{5F}{9}-\frac{160}{9}$
Multiply all terms by 9 in order to eliminate fractions.
$9C=5F-160$
Add 160 to both sides.
$9C+160=5F$
Divide both sides by 5.
$F=\frac{9C+160}{5}$
