## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 2 - Section 2.2 - An Introduction to Problem Solving - Exercise Set - Page 67: 61

#### Answer

Halogen bulb $= 4000$ bulb hours Fluorescent bulb $= 100,000$ bulb hours Incandescent bulb $= 1500$ bulb hours.

#### Work Step by Step

Let Number of bulb hours for Halogen bulb be $x$. Fluorescent bulb $25$ times the number of bulb hours for a halogen bulb $= 25 x$ Incandescent bulb is $2500$ less than the number of bulb hours for a halogen bulb $= x-2500$ Total Number of bulb hours $=105,500$ $x+25x+x-2500=105500$ Add like terms. $27x-2500=105500$ Add $2500$ on both sides. $27x-2500+2500=105500+2500$ $27x = 108000$ $x=\frac{108000}{27}$ $x =4000$ Number of bulb hours for Halogen bulb $(x) = 4000$. Fluorescent bulb $=25x$ $= 25(4000)$ $=100,000$ Incandescent bulb $= x-2500$ $=4000-2500$ $=1500$

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