Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.2 - An Introduction to Problem Solving - Exercise Set: 34

Answer

Scores: 526, 527, and 528.

Work Step by Step

The first integer is represented by $x$. Second integer = $(x+1)$. Third integer = $(x+2)$. The sum of the first, second, and 3 times the third integers = $2637$. Rewritten: $x+(x+1)+3(x+2) = 2637$ Simplify: $x+x+1+3x+6 = 2637$ Simplify: $5x+7 = 2637$ Isolate $x$: $\frac{5x+7 = 2637}{-7}$ -> $\frac{5x=2630}{5}$ Solve for $x$: $x = 526$. Plug $x$ back into the integers: $(526), (526+1), (526+2)$ The scores are: $526, 527, 528$.
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