Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Review - Page 112: 38

Answer

$x=\dfrac{y-y_1+mx_1}{m}$

Work Step by Step

Using the properties of equality, in terms of $x$, the given expression, $ y-y_1=m(x-x_1) ,$ is equivalent to \begin{array}{l}\require{cancel} y-y_1=mx-mx_1 \\\\ y-y_1+mx_1=mx \\\\ \dfrac{y-y_1+mx_1}{m}=\dfrac{m}{m}x \\\\ x=\dfrac{y-y_1+mx_1}{m} .\end{array}
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